Question

$2$ flask of equal volume has been joined by a narrow tube of negligible volume. Initially both flask are at $300k$ containing $0.6mole{O}_2$ gas at $0.5atm$ pressure. One of the flask is then placed in thermostate at $600K$. Calculate find pressure and mole of $O_2$ gas in each flask.

Answer 1

Initially, for both flasks,

$PV=nRT$

$0.5\times V=0.6\times R\times 300$

$V=360R$

Finally,

For flask 1,

$P\left(360R\right)=xR300$

$x=1.2P$

For flask 2,

$P\left(360R\right)=yR600$

$y=0.6P$

Here, total no moles will remain constant,

$n=x+y$

$0.6=1.2P+0.6P$

$P=1/3$ atm

So now, no of moles,

$x=1.2\times 1/3=0.4$ mol

$y=0.6\times 1/3=0.2$ mol

Therefore, the two flasks will contain 0.4 mol and 0.2 mol.