Question

Two flask of equal volume have been joined by a narrow tub of negligible volume. Initially both flasks are at 300 K containing 0.60 mole of $O_2$ gas at 0.5 atm pressure. One of the flask is then placed in a thermostat at 600 K. Calculate final pressure and the number of $O_2$ gas in each flask.

Answer 1

$PV=nRT$

$\Rightarrow 0.5\times V=0.6\times R\times 300$

$\therefore V=360R$

In $2^{nd}$ case, the pressure will be same

Flask 1: $PV=aRT$

$\Rightarrow P\left(360R\right)=aR\left(300\right)$

$\Rightarrow a=1.2P$

Flask 2: $PV=bRT$

$\Rightarrow P\left(360R\right)=bR\left(600\right)$

$\Rightarrow b=0.6P$

$\Rightarrow a+b=1.2P+0.6P=1.8P=0.6$

$\Rightarrow P=0.33$

$\therefore a=0.396,b=0.198$ .