CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
150
You visited us 150 times! Enjoying our articles? Unlock Full Access!
Question

Two flasks of equal volume have been joined by a narrow tube of negligible volume. Initially, both flasks are at 300K containing 0.6 mole of O2 at 0.5 atm pressure. one of the flasks is placed in the thermostat of 600K. FInd the number of mole of O2 gas in each flask.

A
0.5mol and 0.3 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.5mol and 0.2 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.4mol and 0.2 mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.6mol and 0.3 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.4mol and 0.2 mol
0.5V1=0.6R×300
V=360R
in 2nd case the pressure will be same for both flask and sum of moles is 0.6
Flask-1
P×360R=n1R×300
n1=1.2P
Flask-2
P×360R=n2R×600
n2=0.6P
n1+n2=0.6
1.2P+0.6P=0.6
1.8P=0.6
Final pressure-
P=13
Number of moles of oxygen in flasks-
n1=1.2×13=0.4
n2=0.6×13=0.2

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Dalton's Law of Partial Pressure
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon