2 moles of A 3 moles of B are mixed in 1 litre vessel and the reaction is carried at 400-C according to the equation- A-B- 2C-The equilibrium constant of the reaction is 4- Find the number of moles of C at equilibrium-

4 moles of A are mixed with 4 moles of B, then 2 moles of C are formed at equilibrium, according to the reaction,
A + B $⇌$ C + D.
The equilibrium constant is :

4

moles of

A

are mixed with

4

moles of

B

when

2

moles of

C

are formed at equilibrium according to the reaction

A + B ⇌ C + D

The value of the equilibrium constant is :

4 m o l e s

of A are mixed with

4 m o l e s

of B when

2 m o l e s

of C are formed at equilibrium. According to the equation

A + B ⇋ C + D

. Find the equilibrium constant:

4 moles of A are mixed with 4 moles of B, then 2 moles of C are formed at equilibrium, according to the reaction,
A + B $⇌$ C + D.
The equilibrium constant is :

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2 moles of A & 3 moles of B are mixed in 1 litre vessel and the reaction is carried at 400∘C according to the equation; A+B⇌2C.The equilibrium constant of the reaction is 4. Find the number of moles of C at equilibrium.

The correct option is A 2.4 mole A+B⇌2C.At t=0 2 3 -at eqm 2-x 3-x 2x soK=(2x)2/(2−x)(3−x)=4;x=1.2So, the no. of moles of C at equation are 2x = 2.4 moles.Hence, the correct option is A

2 moles of A & 3 moles of B are mixed in 1 litre vessel and the reaction is carried at $400^{\circ}$ C according to the equation; $A + B ⇌ 2 C .$ The equilibrium constant of the reaction is 4. Find the number of moles of C at equilibrium.

The correct option is A 2.4 mole
$A + B ⇌ 2 C .$
At t=0 2 3 -
at eqm 2-x 3-x 2x so

$K = (2 x)^{2} / (2 - x) (3 - x) = 4; x = 1.2$

So, the no. of moles of $C$ at equation are 2x = 2.4 moles.

Hence, the correct option is $A$