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Question

2. x sin 3x

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Solution

The integral is given below as,

I= xsin3x dx

Use integration by parts rule. Consider x as first function and sin3xas second function.

I=x sin3xdx ( d dx x sin3xdx )dx =x( cos3x 3 ) ( cos3x 3 ) dx = xcos3x 3 + 1 3 ( sin3x 3 )+C I= xcos3x 3 + 1 9 sin3x+C

Thus, the integration of xsin3x dx is xcos3x 3 + 1 9 sin3x+C.


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