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Byju's Answer
Standard XII
Chemistry
Ion Electron Method
20 mL solutio...
Question
20
m
L
solution of
0.1
M
ferrous sulphate was completely oxidised using a suitable oxidising agent. What is the number of electrons exchanged?
A
1.204
×
10
22
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B
193
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C
1930
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D
1.204
×
10
21
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Solution
The correct option is
D
1.204
×
10
21
During oxidation of
F
e
S
O
4
,
F
e
2
+
ion is oxidises into
F
e
3
+
ion.
F
e
2
+
⟶
F
e
3
+
+
e
−
i.e.,
1
e
−
is transferred from
1
molecule of
F
e
S
O
4
,
i.e., from
1
F
e
2
+
ion.
Now, molarity of
F
e
S
O
4
solution
=
0.1
M
and volume of solution
=
20
m
L
=
20
1000
L
∴
Number of moles
=
0.1
×
20
1000
=
0.002
∵
In
1
mole
F
e
S
O
4
, number of molecules
=
6.022
×
10
23
∴
In
0.002
mole
F
e
S
O
4
, number of molecules
=
6.022
×
10
23
×
0.002
=
1.204
×
10
21
∴
Number of electrons transferred
=
1.204
×
10
21
Suggest Corrections
0
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