You visited us 1 times! Enjoying our articles? Unlock Full Access!

Anomalous Behavior of Lithium Halogens

What is the v...

Question

What is the volume (in ml) of 0.1 M potassium permanganate solution required to completely oxidise 100 ml of 0.5 M ferrous sulphate solution in acidic medium?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B 100

Given parameters are:
$M_{1} = 0.1 M$
$M_{2} = 0.5 M$
$V_{1} = ?$
$V_{2} = 100 m l$
Balanced equation is:
$10 F e S O_{4} + 2 K M n O_{4} + 8 H_{2} S O_{4} = 5 F e_{2} S O_{4} + 2 M n S O_{4} + K_{2} S O_{4} + 8 H_{2} O$
Thus no. of moles of $K M n O_{4}$ , $n_{1}$ is 2
and of $F e S O_{4}$ , $n_{2}$ is 10.
Thus formula based on the concept of stoichiometry.
$n_{2} \times M_{1} \times V_{1} = n_{1} \times M_{2} \times V_{2}$
$10 \times 0.1 \times V_{1} = 2 \times 0.5 \times 100$
$V_{1} = 100 m l$
Therefore volume will be 100 ml.
Thus, Option D is correct.

Suggest Corrections

Similar questions

K M n O_{4}

20 m L

0.1 M

(N_{2} H_{6} S O_{4})

100

10

20

\frac{M}{50}

1

4 F e^{3 +} + N_{2} H_{4} \to N_{2} + 4 F e^{2 +} + 4 H^{⨁}

M n O_{4}^{⊝} + 5 F e^{2 +} + 8 H^{⨁} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O

H_{2} C_{2} O_{4}

N a H C_{2} O_{4}

2.02 g

1

10

3.0

0.1 N

10.0

4.0

0.1

H_{2} C_{2} O_{4}

K M n O_{4}

H_{2} O_{2}

K M n O_{4}

Join BYJU'S Learning Program