Question

$200MeV$ of energy can be obtained by per fission. In a reactor generating $100kW$ find the number of nuclei under going the fission per second -

• A. $1000$
• B. $2\times {10}^8$
• C. $3.125\times {10}^{15}$
• D. $931$

Answer 1

The correct option is C $3.125\times {10}^{15}$

Energy released per fission$=200$MeV

Total energy released per second$=100$kW

If n is the number of fissions per second

Total energy released per second$=n\times$ Energy per fission

$100\times {10}^3=n\times 200$MeV

$100\times {\omega }^3\frac{5}{3}=n\times 200\times {10}^6\times 1.6\times {10}^{-19}\frac{5}{3}$

$n=3.125\times {10}^{15}$ $\frac{fissions}{sec}$.