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Question

25g of 80% pure CaCO3 is made to react with excess of HCl. Calculate volume of CO2 evolved at NTP.


A

1.18 L

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B

2.28 L

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C

3.38 L

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D

4.48 L

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Solution

The correct option is D

4.48 L


From the question, it is a volume-volume problem.
The balanced reaction CaCO3+2HCl CaCl2+CO2+H2O
25 g of 80 % pure CaCO3×25X80100 =20g of CaCO3
From reaction, 1 mole of CaCO3 gives 1 mole of CO2
At NTP, 1 mole of CaCO3 = 22.4 L of CO2
100g of CaCO3 = 22.4 L of CO2
20g of CaCO3=( 22.4 X20)/100 = 4.48 L


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