Calculate the volume of $C O_{2}$ evolved at NTP when 20g of $C a C O_{3}$ is heated strongly.

3.38 L

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4.48

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5.58 L

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6.68 L

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Solution

The correct option is B
4.48

The question gives weight of reactants and asks the volume of product. So, it is a weight-volume problem. Start by balancing the reaction

$C a C O_{3}$ $\to$ $C a O$ + $C O_{2 (g)}$ $↑$

$∴$ 1 mole of $C a C O_{3}$ gives 1 mole of $C O_{2}$

From Avagadro's Law, 1 mole of $C O_{2}$ at NTP occupies 22.4L

$∴$ 1 mole of $C a C O_{3}$ = 22.4 L of $C O_{2}$
100g = 22.4L of $C O_{2}$

$∴$ 20g = 20 $\times$ $\frac{22.4}{100}$ = 4.48 L of $C O_{2}$

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Calculate the volume of $C O_{2}$ evolved at NTP when 20g of $C a C O_{3}$ is heated strongly.

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