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Question

# Calculate the volume of CO2 evolved at NTP when 20g of CaCO3 is heated strongly.

A

3.38 L

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B

4.48

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C

5.58 L

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D

6.68 L

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Solution

## The correct option is B 4.48 The question gives weight of reactants and asks the volume of product. So, it is a weight-volume problem. Start by balancing the reaction CaCO3 → CaO + CO2(g) ↑ ∴ 1 mole of CaCO3 gives 1 mole of CO2 From Avagadro's Law, 1 mole of CO2 at NTP occupies 22.4L ∴ 1 mole of CaCO3 = 22.4 L of CO2 100g = 22.4L of CO2 ∴ 20g = 20 × 22.4100 = 4.48 L of CO2

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