Question

$26$ $c{m}^3$ of $C{O}_2$ is passed over red hot coke. The volume of $CO$ evolved (in $c{m}^3$) is:

• A. $15$
• B. $10$
• C. $32$
• D. $52$

Answer 1

The correct option is D $52$

$C{O}_2+C\to 2CO$

Thus, one mole of carbon dioxide will give two moles of carbon monoxide.
At STP, one mole of a gas occupies $22.4$ L.

Hence, $22.4$ L of carbon dioxide will give $44.8$ L of carbon monoxide.

$26$ $c{m}^3$ of carbon dioxide will give $26\times \frac{44.8}{22.4}=52$ $c{m}^3$ of carbon monoxide.