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Question

2713Al is a stable isotope. 2913Al is expected to decay by :

A
α emission
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B
β emission
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C
Positron emission
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D
Proton emission
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Solution

The correct option is B β emission
13Al29 is neutron rich isotope, will decay by β emission converting some of its neutron itno proton as
0n11β0+1H1

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