2713Al is a stable isotope. 2913Al is expected to decay by :
A
α− emission
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B
β− emission
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C
Positron emission
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D
Proton emission
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Solution
The correct option is Bβ− emission 13Al29 is neutron rich isotope, will decay by β− emission converting some of its neutron itno proton as 0n1→−1β0+1H1