Question

272 calories of heat energy is required to heat 0.02 kg of a metal of specific heat capacity 170 cal/kg/°c to a temp.T,if the initial temp. of the metal is 20 °c,calculate the final temp.?

Answer 1

Dear Student

$$\begin{gathered} HeatenergyQcanbegivenas \\ Q=mc∆T \\ Q=mc\left(T_f-T_i\right) \\ {T}_f=\frac{Q}{mc}+T_i \\ {T}_f=\frac{272cal}{\left(0.02\right)\left(170cal/kg.{}^{o}C\right)}+{20}^{o}C \\ {T}_f={80}^{o}C+{20}^{o}C={100}^{o}C \end{gathered}$$

Regards