Ddx2x2+13x+2=ddx6x3+4x2+3x+2=6ddxx3+4ddxx2+3ddxx+ddx2=63x2+42x+31+0=18x2+8x+3 ...

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2 x2+13 x+2

Question

(2x² + 1) (3x + 2)

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Solution

$\frac{d}{d x} ((2 x^{2} + 1) (3 x + 2)) = \frac{d}{d x} (6 x^{3} + 4 x^{2} + 3 x + 2) = 6 \frac{d}{d x} (x^{3}) + 4 \frac{d}{d x} (x^{2}) + 3 \frac{d}{d x} (x) + \frac{d}{d x} (2) = 6 (3 x^{2}) + 4 (2 x) + 3 (1) + 0 = 18 x^{2} + 8 x + 3$

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