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Byju's Answer
Standard XII
Chemistry
EMF
3. Given 1) C...
Question
3. Given 1) Cu2+ + 2e- = Cu , E0=0.337V 2) Cu2+ + e- = Cu+ , E0=0.153V electrode potential for the reaction Cu+ + e- = Cu, will be?
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Q.
1.
C
u
2
+
+
2
e
−
⟶
C
u
,
E
0
=
0.337
V
2.
C
u
2
+
+
e
−
⟶
C
u
+
,
E
0
=
0.153
V
Electrode potential,
E
0
for the reaction
C
u
+
+
e
−
⟶
C
u
Q.
Given (i)
C
u
2
+
+
2
e
−
→
C
u
,
E
o
=
+
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
E
o
=
+
0.153
V
Electrode potential,
E
0
for the reaction will be:
C
u
+
+
e
−
→
C
u
Q.
Given :
(i)
C
u
2
+
+
2
e
−
→
C
u
,
E
∘
=
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
,
E
∘
=
0.153
V
Elctrode potential,
E
∘
for the the reaction,
C
u
+
+
e
−
→
C
u
,
will be
Q.
Given:
(i)
C
u
2
+
+
2
e
−
→
C
u
,
E
∘
=
0.337
V
(ii)
C
u
2
+
+
e
−
→
C
u
+
,
E
∘
=
0.153
V
Electrode potential,
E
∘
for the reaction,
C
u
+
+
e
−
→
C
u
, will be
Q.
The standard reduction potentials for
C
u
2
+
/
C
u
and
C
u
2
+
/
C
u
+
are
0.337
V
and
0.153
V
respectively. The standard electrode potential of
C
u
+
/
C
u
half cell is:
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