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Ways to Define Concentration

3 litre aqueo...

Question

$3$ litre aqueous solution is prepared by dissolving $4.9$ gram $H_{2} S O_{4}$ in water. To calculate pH of this solution, there is need to calculate moles $H_{2} S O_{4}$ . Which of the following formula you would use?

Mole of

H_{2} S O_{4} = \frac{M o l e c u l a r m a s s}{l i t r e}

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Mole of

H_{2} S O_{4} = \frac{W e i g h t o f s u b s t a n c e}{M o l e c u l a r m a s s}

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Mole of

H_{2} S O_{4} = \frac{M o l e c u l a r m a s s}{W e i g h t o f s u b s t a n c e}

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Mole of

H_{2} S O_{4} = \frac{W e i g h t o f s u b s t a n c e}{l i t r e}

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Solution

The correct option is B Mole of $H_{2} S O_{4} = \frac{W e i g h t o f s u b s t a n c e}{M o l e c u l a r m a s s}$
Mole of $H_{2} S O_{4} = \frac{W e i g h t o f s u b s t a n c e}{M o l e c u l a r m a s s}$

Mole of $H_{2} S O_{4}$ is found out by dividing weight of substance by molecular mass.

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