Question

$3$ moles of $A$ and $4$ moles of $B$ are mixed together and allowed to cime into equilibrium according to the following reaction
$3A_{\left(g\right)}+4B_{\left(g\right)}\rightleftharpoons 2C_{\left(g\right)}+3D\left(g\right)$
When equilibrium is reached, there is $1$ mole of $C$. The equilibrium extent of the reaction is:

• A. $\frac{1}{4}$
• B. $\frac{1}{3}$
• C. $\frac{1}{2}$
• D. $1$

Answer 1

The correct option is B $\frac{1}{3}$

$3A+4B\rightleftharpoons 2C+3D$

when equilibrium is reacted, there is 1 mole of C

$3A+4B\rightleftharpoons 2C+3D$

initial mole $3423$

at equilbrium $3-x4-x2-x3-x$ [where x = 1 ]

So final mole $2312$

Equilibrium constant $=\left[C\right]\left[D\right]/\left[A\right]\left[B\right]$

$=1\times 2/2\times 3=2/6$

$=\frac{1}{3}$

Ans $B)\frac{1}{3}$