The correct option is A 180 Given, nbsp;( 3) × ( 2) × (5) × ( 6) × ( 1) × 1 If the number of negative integers in a product is even, then the product is a p ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties of Multiplication of Integers

-3 ×-2 ×5 ×-6...

Question

$(- 3) \times (- 2) \times (5) \times (- 6) \times (- 1) \times 1 =$

$- 180$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$120$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$180$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$- 120$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$180$

Given, $(- 3) \times (- 2) \times (5) \times (- 6) \times (- 1) \times 1$

If the number of negative integers in a product is even, then the product is a positive integer.

In the given product the number of negative integers is 4. So the resultanat product will be positive.

$\Rightarrow (3 \times 2) \times (5) \times (- 6 \times - 1) \times 1$

$= (6) \times (5) \times (6) \times 1$

$= 30 \times (6)$

$= 180$

Suggest Corrections

Similar questions

{[\frac{- 1 + i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 + i \sqrt{3}}{2}]}^{5} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{5} =

{[\frac{- 1 + i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{6} + {[\frac{- 1 + i \sqrt{3}}{2}]}^{5} + {[\frac{- 1 - i \sqrt{3}}{2}]}^{5} =

Question 4(d) :

Look at the figures and write ‘<’ or ‘>’ between the given pairs of fractions:

$\frac{6}{6} □ \frac{3}{3}$

Using appropriate properties, find:

i) $- \frac{2}{3} \times \frac{3}{5} + \frac{5}{2} - \frac{3}{5} \times \frac{1}{6}$

ii)

\frac{2}{5} \times (\begin{matrix} - \frac{3}{7} \end{matrix}) - \frac{1}{6} \times \frac{3}{2} + \frac{1}{14} \times \frac{2}{5}

Question 4(e) :

Look at the figures and write ‘<’ or ‘>’ between the given pairs of fractions:

$\frac{5}{6} □ \frac{5}{5}$

Join BYJU'S Learning Program

(−3)×(−2)×(5)×(−6)×(−1)×1=

$(- 3) \times (- 2) \times (5) \times (- 6) \times (- 1) \times 1 =$