3x
The integral is,
y = ∫ ( 4 e 3 x + 1 ) d x
Here, y is the solution of integral.
Use the formula of ∫ e x d x = e x + A , where A is constant.
= ∫ ( 4 e 3 x + 1 ) d x = ∫ ( 4 e 3 x + 1 ) d x = 4 ∫ e 3 x d x + ∫ d x = 4 e 3 x 3 + x + A
Thus, the solution of integral is 4 e 3 x 3 + x + A .
The integral is,
Here,
Use the formula of
Thus, the solution of integral is
