Question

# 3x

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Solution

## The integral is, y= ∫ ( 4 e 3x +1 ) dx Here, y is the solution of integral. Use the formula of ∫ e x dx = e x +A, where A is constant. = ∫ ( 4 e 3x +1 ) dx = ∫ ( 4 e 3x +1 ) dx =4 ∫ e 3x dx+ ∫ dx = 4 e 3x 3 +x+A Thus, the solution of integral is   4 e 3x 3 +x+A.

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