Given: 3x2 + 34x + 11 = 0
On splitting the middle term 34x as x + 33x, we get:
3x2 + x + 33x + 11 = 0
x(3x + 1) + 11(3x + 1) = 0
(3x + 1) (x + 11) = 0
We know that if the product of two numbers is zero, then at least one of them must be zero.
Thus,
3x + 1 = 0 or x + 11 = 0
x = – or x = –11
Therefore, the solution of the given equation is x = –11, – .