Question

$4.4g$ of an unknown gas occupies $2.24L$ of volume at standard temperature and pressure. The gas may be:

• A. Carbon dioxide
• B. Carbon monoxide
• C. Oxygen
• D. Sulphur dioxide

Answer 1

Answer: (A)

Carbon dioxide

$\because 2.24L$ of gas has mass $=4.4gm$

$\therefore 22.4L$ of gas has mass $=\frac{4.4}{2.24}\times 22.4=44$

So, given gas is $C{O}_2$ because $C{O}_2$ has molecular mass $=44.$