Question

4 mole of $A$ are mixed with 4 mole of $B$ so, 2 moles of $C$ are formed at equilibrium according to the following reaction,

$A+B$ $\rightleftharpoons$ $C+D$

The value of the equilibrium constant is:

• A. $1$
• B. $4$
• C. $\frac{1}{4}$
• D. $\frac{1}{2}$

Answer 1

The correct option is A $1$

$A+B\rightleftharpoons C+D$
Initial conc. 4 4 0 0
Eqm conc. 4-x 4-x 2 2

Let's assume volume= V Liter

$K_C=\frac{\left[C\right]\left[D\right]}{\left[A\right]\left[B\right]}=\frac{2/V\times 2/V}{2/V\times 2/V}=1$

Hence, the correct option is A.