Question

4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction $A+B\rightleftharpoons C+D$, 2 moles of C and D are formed.

The equilibrium constant for the reaction will be-

• A. 1/4
• B. 1/2
• C. 1
• D. 4

Answer 1

Answer: (C)

1

The initial concentrations of A, B, C, and D are 4M, 4M, 0M, and 0M respectively.

The equilibrium concentrations of A,B,C and D are $4-2=2M$, $4-2=2M$, 2M and 2M respectively.

The expression for the equilibrium constant is $=\frac{\left[C\right]\left[D\right]}{\left[A\right]\left[B\right]}=\frac{2\times 2}{2\times 2}=1.$