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Stoichiometric Calculations

400 m3 of ace...

Question

$400 m^{3}$ of acetylene is allowed to combust stoichiometrically in air. The volume of gaseous $(i n m^{3})$ products obtained after combustion is .
(It is give that air has 20% v/v $O_{2}$ ))

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Solution

Balanced reaction for combustion of acetylene:
$C_{2} H_{2} (A) + \frac{5}{2} O_{2} (B) ⟶ 2 C O_{2} (C) + H_{2} O (D)$
Mole ratio of species, $A : B; C : D = 1 : 2.5; 2 : 1$
According to Avogadro's law, $n \propto V$
Volume ratio of species, $A : B; C : D = 400 m^{3} : 1000 m^{3}; 800 m^{3} : 400 m^{3}$
Since only 20 ml oxygen is present per 100 ml of air. So 80 ml of air is left unreacted per 20 ml of oxygen.
Air left when $1000 m^{3}$ oxygen reacted $= 1000 \times \frac{80}{20} = 4000 m^{3}$
Total volume of gaseous product $4000 + 800 + 400 = 5200 m^{3}$

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