The correct option is A (7y 1+5x)(7y 1 5x) We have, #160; 49y^2 14y+1 25x^2 #160; #160; #160; #160; #160; #160; #160; #160; ...

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Multiplication of Two Binomials

49y2-14y+1-25...

Question

$49 y^{2} - 14 y + 1 - 25 x^{2} =$

(7 y - 1 + 5 x) (7 y - 1 - 5 x)

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(5 x - 1 + 7 y) (5 x - 1 - 7 y)

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(7 y - 1 + 5 x) (7 y - 1 + 5 x)

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(5 x + 7 y - 1) (5 x + 7 y + 1)

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Solution

The correct option is A $(7 y - 1 + 5 x) (7 y - 1 - 5 x)$
We have, $49 y^{2} - 14 y + 1 - 25 x^{2}$
$= (7 y - 1)^{2} - 25 x^{2}$ $(∵ a^{2} - 2 a b + b^{2} = (a - b)^{2})$
$= (7 y - 1 + 5 x) (7 y - 1 - 5 x)$ $(∵ a^{2} - b^{2} = (a + b) (a - b))$

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