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Question

4x4 - 5x2 +1

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Solution

4x⁴ - 5x² + 1= 0
x⁴ = y²
x² = y ( substituiT)

4x⁴ - 5x² + 1= 0

4y² - 5y + 1 = 0

ax² + bx + c = 0

4y² - 5y + 1 = 0
a = 4

b = - 5

c = 1

Δ = b² - 4ac

Δ = (-5)² - 4(4)(1)

Δ = + 25 - 16

Δ = + 9


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