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Question

5kg of ice at 10oC is added to 5kg of water at 10oC. The temperature of the resulting mixture will.

A
10oC
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B
0oC
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C
3.3oC
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D
10oC
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Solution

The correct option is B 0oC
Required heat to decrease temperature of ice 0oC and then melt to water =5000×0.5×(+10)+5000×80=(25000cal+400000cal)=425000cal=425kcal
Heat released by water to reach 0oC =5000×1×(10)=50000cal=50kcal
Required heat more than released heat, all the ice will not melt and the final temperture will be 0oC

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