5 $m l$ of a gaseous hydrocarbon( $C_{x} H_{y}$ ) was exploded with 30 $m l$ of oxygen. The resulting gas on cooling to room temperature is found to measure 25 $m l$ of which 10 $m l$ are absorbed by $N a O H$ and the remainder by pyrogallol. The value of x+y is?

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Solution

Balanced equation
$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} ⟶ x C O_{2} + \frac{y}{2} H_{2} O_{(l)}$

5 $m L$ 30 $m L$

0 $30 - 5 (x + \frac{y}{4})$

5x

since 5x=10 $\Rightarrow$ x=2

$30 - 5 (x + \frac{y}{4}) = 15 \Rightarrow y = 4$

Therefore formula of hydrocarbon = $C_{x} H_{y}$

x + y = 2 + 4 = 6

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Similar questions

5 $m l$ of a gaseous hydrocarbon( $C_{x} H_{y}$ ) was exploded with 30 $m l$ of oxygen. The resulting gas on cooling to room temperature is found to measure 25 $m l$ of which 10 $m l$ are absorbed by $N a O H$ and the remainder by pyrogallol. The value of x+y is?

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5 ml of a gaseous hydrocarbon(CxHy) was exploded with 30 ml of oxygen. The resulting gas on cooling to room temperature is found to measure 25 ml of which 10 ml are absorbed by NaOH and the remainder by pyrogallol. The value of x+y is? ___

Balanced equation CxHy+(x+y4)O2⟶xCO2+y2H2O(l) 5 mL 30 mL 0 30−5(x+y4) 5x since 5x=10 ⇒ x=2 30−5(x+y4)=15⇒y=4 Therefore formula of hydrocarbon = CxHy x + y = 2 + 4 = 6

5 $m l$ of a gaseous hydrocarbon( $C_{x} H_{y}$ ) was exploded with 30 $m l$ of oxygen. The resulting gas on cooling to room temperature is found to measure 25 $m l$ of which 10 $m l$ are absorbed by $N a O H$ and the remainder by pyrogallol. The value of x+y is?

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