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Question

50.0 mL of 0.10 M HCl is mixed with 50.0 mLof 0.10 M NaOH. The solution's temperature rises by 0.6oC. Calculate the enthalpy of neutralization per mole of HCl.
Given : density and specific heat of solution is 1g mL1 and 4.2 Jg1 C1

A
50.4 kJ/mol
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B
54.4 kJ/mol
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C
57.7 kJ/mol
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D
63.2 kJ/mol
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Solution

The correct option is A 50.4 kJ/mol
Balanced chemical reaction :
HCl+NaOHNaCl+H2O
Milimoles = Molarity × Volume of solution in mL
Milimoles of HCl = 0.1×50=5 mmol
Milimoles of NaOH = 0.1×50=5 mmol
Hence millimoles of acid neutralized = 5 mmol
Specific heat capacity is 4.2 Jg1 C1
Heat released (q)=msT=100×4.2×0.6=252
Enthalpy of neutralization per mole of HCl H=252J×10005=50.4 kJ/mol

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