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Question

50 mL of 1 M oxalic acid (molar mass=126 gmol1) is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. The amount of oxalic acid (in grams) adsorbed per gram of the charcoal is:

A
3.15
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B
1.575
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C
12.6
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D
6.3
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Solution

The correct option is D 6.3
50 mL of 1 M oxalic acid=50×1 mmol
50 mL of 0.5 M oxalic acid=50×0.5 mmol

Thus, oxalic acid adsorbed = 50(10.5)=50×0.5 mmol
=50×0.51000×126 g
=3.15 g
Charcoal taken = 0.5g
Thus, oxalic acid adsorbed per gram of charcoal =3.150.5=6.3 g

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