Question

$540g$ ice at $0^{\circ }$ C is mixed with $540g$ of water at ${80}^{\circ }C$. The final temperature of mixture is

• A. $0^{\circ }C$
• B. ${40}^{\circ }C$
• C. ${80}^{\circ }C$
• D. less than $0^{\circ }C$

Answer 1

Answer: (A)

$0^{\circ }C$

Let the final temperature be $T$,

$mL+mc\Delta T=$heat gained by ice= heat lost by water.

$540\times 336+540\times 4.2\times (T-0)=540\times 4.2\times (80-T)$

$\Rightarrow T=0^{o}C$