5ml of a gaseous hydrocarbon $(C_{x} H y)$ was exploded with 30 ml of oxygen. The resulting gas on cooling to room temperature is found to measure 25ml of which 10ml are absorbed by NaOH and the remainder by Pyrogallol. The value of x + y is?___

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Solution

$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to x C O_{2} + \frac{Y}{2} H_{2} O_{(l)}$
$5 M l 30 M l$
$030 - 5 (x + \frac{y}{4}) 5 x$
$∵ 5 x = 10 \Rightarrow x = 2$
$5 (x + \frac{y}{4}) = 15 \Rightarrow y = 4$
$∴$ formula of Hydrocarbon = $C_{x} H y$
$x + y = 2 + 4 = 6$

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5ml of a gaseous hydrocarbon (CxHy) was exploded with 30 ml of oxygen. The resulting gas on cooling to room temperature is found to measure 25ml of which 10ml are absorbed by NaOH and the remainder by Pyrogallol. The value of x + y is?___

CxHy+(x+y4)O2→xCO2+Y2H2O(l) 5Ml 30Ml 0 30−5(x+y4)5x ∵5x=10⇒x=2 5(x+y4)=15⇒y=4 ∴ formula of Hydrocarbon = CxHy x+y=2+4=6

5ml of a gaseous hydrocarbon $(C_{x} H y)$ was exploded with 30 ml of oxygen. The resulting gas on cooling to room temperature is found to measure 25ml of which 10ml are absorbed by NaOH and the remainder by Pyrogallol. The value of x + y is?___

$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to x C O_{2} + \frac{Y}{2} H_{2} O_{(l)}$
$5 M l 30 M l$
$030 - 5 (x + \frac{y}{4}) 5 x$
$∵ 5 x = 10 \Rightarrow x = 2$
$5 (x + \frac{y}{4}) = 15 \Rightarrow y = 4$
$∴$ formula of Hydrocarbon = $C_{x} H y$
$x + y = 2 + 4 = 6$