$6.02 \times 10^{20}$ molecules of urea are present in $100 m L$ of its solution. The concentration of solution is:

0.02 M

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0.01 M

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0.001 M

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0.1 M

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Solution

The correct option is B $0.01 M$
The concentration of the solution is the ratio of the number of moles of urea to (volume in L) of solution.

The number of mols can b obtained from the ratio of the number of molecules to the Avogadro's number.

$M = \frac{N o o f m o l e s o f s u b s t a n c e}{V o l u m e i n L i t r e} = \frac{\frac{n o . o f p a r t i c l e s}{N_{A}}}{V o l u m e i n L}$

$M = \frac{\frac{6.02 \times 10^{20}}{6.02 \times 10^{23}}}{\frac{100}{1000}} = 0.01 M$

Thus, the concentration of the solution is $0.01 M$ .

Hence, the correct option is $B$

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6.02 × 10²⁰ molecules of urea are present in 100 mL of its solution. Concentration of urea solution is

6.022 \times 10^{20}

100 m l

6.02 \times 10^{20}

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