$6.02 \times 10^{20}$ molecules of urea is present in $100 m L$ of its solution. The concentration of solution is:

0.001 M

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0.01 M

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0.02 M

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0.1 M

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Solution

The correct option is B $0.01 M$
Moles of urea $= \frac{N}{N_{a}} = 0.001$

Given, $V = 100 m l$

Molarity $= \frac{No. of. moles}{Volume of the solution in L} = \frac{0.001}{0.1} = 0.01 M$

Thus, the correct option is $B$

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6.02 × 10²⁰ molecules of urea are present in 100 mL of its solution. Concentration of urea solution is

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