Question

$6.022\times {10}^{22}$ molecules of $N_2$ at NTP will occupy a volume of:

• A. $22.4$ litres
• B. $2.24$ litres
• C. $6.02$ litres
• D. $6.02$ mL

Answer 1

The correct option is B $2.24$ litres

The volume occupied by the 1mole of $N_2=22.4l$

So, the $1mole=6.022\times {10}^{23}$ molecules of $N_2$

$=\frac{22.4}{6.022\times {10}^{23}}$

So, $6.022\times {10}^{22}$molecules of $N_2$ would occupy volume

$=\frac{22.4}{6.022\times {10}^{23}l}\times 6.022\times {10}^{22}$

$=2.24l$

Thus ,the right option is B