Question

$60kg$ of alloy A is mixed with $100kg$ of alloy B. If alloy A has lead and tin in the ratio $3:2$, and alloy B has tin and copper in the ratio $1:4$, then amount of tin in the new alloy is

• A. $36kg$
• B. $44kg$
• C. $53kg$
• D. $80kg$

Answer 1

The correct option is B $44kg$

Quantity of tin in $60kg$ of A $=60\times \frac{2}{5}=24kg$
Quantity of tin in $100kg$ of B $=100\times \frac{1}{5}=20kg$
Quantity of tin in new alloy $=\left(\begin{array}{c}20+24\end{array}\right)=44kg$