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Question

(6abb2+12ac2bc) divided by (6ab) gives .

A
(b+2c)
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B
(b2c)
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C
(2bc)
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Solution

The correct option is A (b+2c)
Given, the expression is
6abb2+12ac2bc(6ab)

Consider the numerator,
6abb2+12ac2bc6ab=6×a×bb2=b×b
Both the terms have b as a common factor.

12ac=2×2×3×a×c2bc=2×b×c
Both the terms have 2 and c as common factors.

By taking the common factors out,
6abb2+12ac2bc=b(6ab)+2c(6ab)
=(b+2c)(6ab)

So, 6abb2+12ac2bc(6ab)=(b+2c)(6ab)(6ab) =(b+2c)

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