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Question

8 L of H2 and 6 L Cl2 are allowed to react to their maximum possible extent. Find out the final volume of reaction mixture. Suppose P and T remains constant throughout the course of reaction.

A
7 L
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B
14 L
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C
2 L
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D
None of these
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Solution

The correct option is B 14 L
H2+Cl22HClVolume before reaction8 L6 L0Volume after reaction 2012
As per stoichiometry,
1 vol. of H2 reacts to form 1 vol. of Cl2 to form 2 vol. of HCl
Limiting reagent will be Cl2 since it is present in less quantity and will be consumed
Volume of mixture after reaction = Volume of H2 left + Volume of HCl formed
Volume of mixture after reaction = 2 + 12 = 14 L.

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