$9000$ square tiles of size $20 c m$ are required to pave the floor of a hall. Find the area of the floor of the hall in $s q . m .$

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Solution

Surface area of one tile $20 \times 20 = 400 c m^{2}$
Total surface area of the tiles $= 9000 \times 400 = 3600000 c m^{2}$
So $,$ surface area pf floor $= 360 m^{2}$
Hence, area of the floor of the hall is $360 m^{2} .$

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9000 square tiles of size 20cm are required to pave the floor of a hall. Find the area of the floor of the hall in sq.m.

Surface area of one tile 20×20=400cm2Total surface area of the tiles=9000×400=3600000cm2So, surface area pf floor =360m2Hence, area of the floor of the hall is 360m2.

$9000$ square tiles of size $20 c m$ are required to pave the floor of a hall. Find the area of the floor of the hall in $s q . m .$

Surface area of one tile $20 \times 20 = 400 c m^{2}$
Total surface area of the tiles $= 9000 \times 400 = 3600000 c m^{2}$
So $,$ surface area pf floor $= 360 m^{2}$
Hence, area of the floor of the hall is $360 m^{2} .$