Question

${{}_{92}U}^{235}$ nucleus absorbs a neutron and disintegrates into ${{}_{54}^{92}Xe}^{139},{{}_{38}Sr}^{94}$ and $X$.

• A. $3$ neutrons
• B. $2$ neutrons
• C. $-\alpha$ particle
• D. $-\beta$ particle

Answer 1

The correct option is B $2$ neutrons

If the uranium disintegrates according to the given reaction the disintegration reaction can be written as:

${}_{92}{U}^{235}\to {}_{54}X{e}^{139}+{}_{38}S{r}^{94}+2{}_0{n}^1$

Hence 2 neutrons will be liberated in the disintegration of uranium.