Question

$9x^2-22x+8=0$

Answer 1

$$\begin{gathered} \text{Given:} \\ \text{9}{x}^2-22x+8=0 \\ \Rightarrow 9x^2-(18x+4x)+8=0 \\ \Rightarrow 9x^2-18x-4x+8=0 \\ \Rightarrow 9x(x-2)-4(x-2)=0 \\ \Rightarrow (x-2)(9x-4)=0 \\ \Rightarrow x-2=0\text{or 9}x-4=0 \\ \Rightarrow x=2\text{or}x=\frac{4}{9} \\ \mathrm{H}\text{ence, the roots of the equation are 2 and}\frac{\text{4}}{9}. \end{gathered}$$