Construction of Parallelogram When Two Adjacent Sides and One Diagonal Are Given.
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Construct a parallelogram ABCD in which AB = 4.3 cm, AD = 4 cm and BD = 6.8 cm.
Construct a parallelogram, one of whose sides is 4.4 cm and whose diagonals are 5.6 cm and 7 cm. Measure the other side.
Construct a parallelogram ABCD in which AB = 5.2 cm, BC = 4.7 cm and AC = 7.6 cm.
By following these steps of construction,
(i) Draw a line segment PQ = 11 cm
(ii) At P construct an angle of 60o and at Q, an angle of 45o.
(iii) Bisect these angles. Let the bisectors of these angles intersect at a point A.
(iv) Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.
(v). Join AB and AC. Triangle ABC has been obtained. In this ∆ABC,
AB + BC + CA > 11cm
AB + BC = 11cm
BC + CA = 11cm
AB + BC + CA = 11cm
AD=4.3cm, DC=5.7cm, DB=7cm
Parallelogram with adjacent sides 7 centimetres and 4 centimetres; one diagonal 8 centimetres.