Exponents with like Bases
Trending Questions
If 52x+1÷25=125, find the value of x.
If ⎡⎣{(172)−2}−13⎤⎦14=7m then find the value of m.
−13
32
−17
28
If and , find the value of .
Question 3(ii)
Find the value of:
(2−1×4−1)÷2−2
- −13
- 28
- −17
- 32
Find the value of x for which (53)−4×(53)−5=(53)3x
If find the value of
Simplify :
(i) a2n−3.a(2n+1)(n+2)(a3)2n+1.an(2n+1)(ii) x2n+7.(x2)3n+2x4(2n+3)
Evaluate :
(i) (3−1×9−1)÷3−2(ii) (3−1×4−1)÷6−1(iii) (2−1+3−1)3(iv) (3−1÷4−1)2(v) (22+32)×(12)2(vi) (52−32)×(23)−3(vii) [(14)−3−(13)−3]÷(16)−3(viii) [(−34)−2]2(ix) {(35)−2}−2(x) (5−1×3−1)÷6−1
Find the value of x for which (49)4×(49)−7=(49)2x−1
If a + b + c = 0, then (a3 + b3 + c3) is equal to-
abc
0
3abc
(ab + bc + ca)
The value of x for which (712)−4×(712)3x=(712)5 is
(a)-1
(b) 1
(c) 2
(d) 3
Question 2(i)
Simplify and express the result in power notation with positive exponent:
(−4)5÷(−4)8
The exponent of in is?
Simplify: .
(i) 3x=81
(ii) 2x−3=1
(iii) 33x−5=19x [4 MARKS]
- amn
- am+n
- amn
Question 69
Find m, so that (29)3×(29)6=(29)2m−1
The middle term in the expansion of is
Find the value of the following expression:
Write the following numbers in the expanded from with exponential notation:
Find x, if
(i) (14)−4×(14)−8=(14)−4x (ii) (−12)−19÷(−12)8=(−12)−2x+1(iii) (32)−3÷(32)5=(32)2x+1 (iv)(25)−3×(25)15=(25)2+3x(v) (54)−x÷(54)−4=(54)5 (vi) (83)2x+1×(83)5=(83)x+2
Simplify and reduce to a simple fraction:
Simplify (25÷28)5 × 2−5.
1210
1220
12(−15)
12(−5)
Question 180(v)
Simplify
(9)3×27×t4(3)−2×(3)4×t2
If an+2 = a2n−1, then the value of n is __.
- 0
3
- 2
- 1
Question 119
Find the value of n.
2n×262−3=218
Question 1(i)
Find the value of:
(i) 26
Evaluate:
(i)(53)2×(53)2
(ii)(56)6×(56)−4
(iii)(23)−3×(23)−2
(iv)(98)−3×(98)2
Simplify: x2y2x5y3
x7y5
x7y7
x5y5
x5y7