Obtaining Centre and Radius of a Circle from General Equation of a Circle
Trending Questions
Q. The equation x2+y2+4x+6y+13=0 represents
Pair of coincident straight lines
Circle
Pair of concurrent straight lines
- Point
Q. Radius of the circle x2+y2+2xcosθ+2ysinθ−8=0, is
- √10
- 1
- 3
- 2√3
Q. A circle x2+y2+2gx+2fy+c=0 passing through (4, 2) is concentric to the circle x2+y2−2x+4y+20=0, then the value of c will be
- -4
- 4
- 0
- 1
Q. The centres of the circles x2+y2=1, x2+y2+6x−2y=1 and x2+y2−12x+4y=1 are
- Same
- Collinear
- Non-collinear
- None of these
Q. The equation of the circle which passes through the points (1, 0), (0, −6) and (3, 4) is
- 4x2+4y2−142x−47y+138=0
- 4x2+4y2+142x+47y+140=0
- 4x2+4y2−142x+47y+138=0
- 4x2+4y2+150x−49y+138=0
Q. A square is inscribed in the circle x2+y2−2x+4y+3=0, whose sides are parallel to the coordinate axes. One vertex of the square is
- (1+√2, −2)
- (1−√2, −2)
- None of these
- (1−2+√2)
Q. The circle passing through the distinct points (1, t), (t, 1) and (t, t) for all values of ′t′ , passes through the point:
- (−1, 1)
- (1, 1)
- (−1, −1)
- (1, −1)
Q. The equation of the circle circumscribing the triangle formed by the lines x+y=6, 2x+y=4 and x+2y=5 is:
- x2+y2+17x+19y−50=0
- x2+y2−17x−19y−50=0
- x2+y2+17x−19y−50=0
- x2+y2−17x−19y+50=0
Q. The length of the diameter of the circle x2+y2−4x−6y+4=0 is -
- 3
- 9
- 4
- 6
Q. The value of k for which two tangents can be drawn from (k, k) to the circle x2+y2+2x+2y16=0 is
- k ϵ R+
- k ϵ R
- k ϵ (−∞, −4)∪(2, ∞)
- k ϵ (0, 1]