Complement
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If then consists of all multiples of
and throw a die alternatively till one of them gets a and wins the game. Find their respective probabilities of winning, if starts first .
If U = {1, 2, 3, .. , 15}, A = {2, 4}, B = {3, 4, 6, 10, 12, 15}, then (A U C)c is:
{1, 2, 3, 5, 15}
{1, 5, 7, 8, 9, 11, 13, 14}
{3, 4, 6, 10, 12, 15}
{1, 3, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}
If Then, is given by
For universal set U, and sets A, B which are subsets of U, the following information is given
n(U) = 47
n(A) = 18
n(B) = 11, n(A ∩ B) = 10
Then, the number of elements that are neither in A nor B is
If , then find its subsets P such that
If A = {2, 4, 6, 8} and U = {1, 2, 3, 4, 5, 6, 7, 8, 9, }, then A'=
{1, 3, 5, 7, 9}
{1, 3, 5, 6, 9}
{1, 3, 5, 7}
{1, 3, 5, 8, 9}
If A, B and C be the sets such that A∪B=A∪C and A∩B=A∩C then prove that B= C
- A′∪B∪C
- A′∪B
- A′∪C′
- A′∩B
f(x)=(x−a1)(x−a2).....(x−an)
What is limx→a1f(x)? For some a≠a1, a2⋅⋅⋅, an, compute limx→af(x)⋅
For universal set U, and sets A, B which are subsets of U, the following information is given -
n(U) = 47
n(A) = 18
n(B) = 11
n(A ∩ B) = 10
Then, the number of elements that neither in A nor B are
Let A and B be sets. If A∩X=B∩X=Φ and A∪X=B∪X for some set X. Show that A=B.
If A = [ x:x is a multiple of 3] and B = [x:x is a multiple of 5] , then A - B is (¯A means complement of A)