Pressure Potential
Trending Questions
Difference between turgor pressure and pressure potential.
Give any two examples of endosmosis and exosmosis.
Explain the terms exosmosis and endosmosis. How can you demonstrate these processes easily?
What would be the pressure potential of a placcid cell ?
Exosmosis tends to cause the shrinkage of the cell whereas endosmosis tends to swells up the cell.
- True
- False
Cell | π | p |
a | 1.0 | 0.5 |
b | 0.6 | 0.3 |
c | 1.2 | 0.6 |
d | 0.8 | 0.4 |
- b ⟶ c ⟶ d ⟶ a
- c ⟶ b ⟶ a ⟶ d
- d ⟶ c ⟶ a ⟶ b
- b ⟶ d ⟶ a ⟶ c
- 1
- 0
- 10
- 100
What is the direction of net osmotic movement of water of a solution A enclosed in a semipermeable membrane having an osmotic potential −30 bars and pressure potential 5 bars is surrounded in a solution B of osmotic potential−10 bars and pressure potential=0?
- A→B
- B→A
- No movement
- Equal amount
Differentiate between exosmosis and endosmosis.
- No flow of water
- B to A
- A to B
- Equal in both directions
- Positive
- Zero
- Remains same
- Negative
- OP = DPD
- OP = zero
- DPD = Zero
- TP = Zero
- Both Ψs and Ψp are negative
- Ψs is negative and Ψp is positive
- Ψp is negative and Ψs is positive
- Both Ψp and Ψs are positive
- Concentration of the salt is the same inside the cell as outside
- Cell bursts
- Diffusion pressure is the same on inside the cell as outside
- Concentration of the water is the same inside the cell as outside
- More negative water potential
- Negative water potential
- More positive water potential
- Positive water potential
What happens when a pressure greater than the atmospheric pressure is applied to pure water or a solution?
- ψs(X)=−8 bar: ψp(X)=7 bar
ψs(Y)=−3 bar: ψp(Y)=1 bar - ψs(X)=−5 bar: ψp(X)=3 bar
ψs(Y)=−5 bar: ψp(Y)=2 bar - ψs(X)=−6 bar: ψp(X)=4 bar
ψs(Y)=−4 bar: ψp(Y)=3 bar - ψs(X)=−6 bar: ψp(X)=5 bar
ψs(Y)=−7 bar: ψp(Y)=2 bar
- - 44 unit
- - 26 unit
- - 3.88 unit
- 26 unit
- Plasmolysed
- Turgid
- Flaccid
- Incipient
- Ψs=−OP
- Ψs=OP
- OP−Ψs=0
- ΨsOP=0