Ambidentate Ligands
Trending Questions
What is meant by unidentate, didentate and ambidentate ligands? Give two examples for each.
- bidentate
- ambidentate
- chelate
- monodentate
What is the number of donor atoms in dimethylglyoximato ligand?
1
2
3
4
Is a strong ligand?
Is water a bidentate ligand?
- It has three isomers, two of them are optically active and one is optically inactive
- It has three isomers, all of them are optically active.
- It has isomers, all of them are optically inactive.
- It has one optically active isomer and two geometrical isomers.
Is H2O an ambidentate ligand or a unidentate ligand?
- SO2−3
- CN−
- NH3
- H2O
Name the type of isomerism when ambidentate ligands are attached to central metal ion. Give two examples of ambidentate ligands.
In the following questions a statement of assertion (A) followed by a statement of reason (R) is given. Choose the correct answer out of the following choices.
(a) Assertion and reason both are true, reason is correct explanation of assertion.
(b) Assertion and reason both are true but reason is not the correct explanation of assertion.
(c) Assertion is true, reason is false.
(d) Assertion is false, reason is true.
Assertion (A) Linkage isomerism arises in coordination compounds containing ambidentate ligand.
Reason (R) Ambidentate ligand has two different donor atoms.
Ethylene Diamine is a____.
Can a didentate ligand act also as an ambidentate ligand ?
- TeBr4
- TeCl4
- XeO2F2
- SF4
(i) It is a neutral ligand.
(ii) It is a didentate ligand.
(iii) It is a chelating ligand.
(iv) It is a unidentate ligand.
- (i). (ii) and (iii)
- (ii) and (iii)
- (iii) and (iv)
- (i), (iii) and (iv)
where:
X = Number of compounds when both Br− are at cis position.
Y = Number of compounds when both Br− are at trans position.
- Ionisation isomers
- Linkage isomers
- Coordination isomers
- Hydrate isomers
- R−H|C|−OHO−
- R−H|C|O−−O−
- R−H|C|H−Cl
- R−C|H=O
- NH3 is a gas while NH+4 in liquid form
- NH3 undergoes sp3 hybridisation while NH+4 undergoes sp3d hybridisation
- NH+4 ion does not have any lone pair of electrons
- NH+4 ion has one unpaired electron while NH3 has two unpaired electrons.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertion and Reason are incorrect
In hte following list-I contains some complex and list-II contains the characterestics of complex.
List-IList-II(Compounds)(I) [Pt(NO2)2(en)2]2+(P) Stable according to EAN-Rule(II) [Cr(π−C6H6)(NO)2](Q) Both ligands acts as ambidentate(III) [Ir(SCN)(SO4)(NH3)4](R) Bond order M - L bond > 1.0(IV)[V(C2H4)(CN)5](S) Bond order of Ligands decreases(T) Co−ordination number of central metal is six
Which of the following options has the correct combination considering List-I and List-II?
- I, Q
- IV, Q
- I, R
- II, P
A research guide instructed his two students to synthesize complex
[Co(NH3)5(NO2)]Cl2
They synthesized the complexes with identical molecular formula, molar mass, geometry, conductance and spin, but they differed in colour. Bases on the above facts the following question.
(ii) Which of the ligands can show ambient property?
NO2
H2O
CO2−3
NH3
(i) Write the electronic configuration of d4 ion.
(ii) What type of hybridisation will Mn+ ion has?
(iii) Name the type of isomerism exhibited by this complex.
where:
X = Number of compounds when both Br− are at cis position.
Y = Number of compounds when both Br− are at trans position.
Unidentate ligands with more than one co-ordinating atoms are called as
Organic ligands
Positive ligands
Ambidentate ligands
Neutral ligands
- tetradentate
- bidentate
- hexadentate
- tridentate
The formation of PH+4 is difficult compared to NH+4 because:
lone pair of phosphorous resides in sp3 orbital
lone pair of phosphorous resides in almost pure p – orbital
lone pair of phosphorous in almost pure s – orbital
lone pair of phosphorous is optically inert.
- NCS−, C2O2−4
- NO−3, SCN
- N−3, NO−2
- CN−, NO−2