Basic Lead Carbonate
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- Tl and Pb
- Sn and Bi
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(P) Fe(CO)5
(Q) CO
(R) H3B←CO
(S) [Mn(CO)5]−
- R>Q>P>S
- S>P>R>Q
- Q>S>P>R
- P>R>S>Q
- Cl−>F−>Br−>I−
- F−>Cl−>Br−>I−
- I−>Br−>F−>Cl−
- I−>Br−>Cl−>F−
Lead pipes are not suitable for drinking water because
A layer of lead dioxide is deposited over pipes
Lead reacts with air to form litharge
Lead forms basic lead carbonate
Lead reacts with water containing air to form Pb(OH)2
- Fehling's Solution
- Fenton's Reagent
- Grignard Reagent
- H2SO4 solution
- Na2[CuCl4]
- Na2[CdCl4]
- Fe4[Fe(CN)6]3
- Na2CrO4
- BeCl2
- MgCl2
- SrCl2
- CaCl2
Which impurities are removed by the following reagents
(b) Lead nitrate solution
An aqueous solution of a salt (A) gives white precipitate (B) with sodium chloride solution. The filtrate gives a black precipitate. (C) When H2S is passed into it. Compound (B) dissolves in hot water and the solution gives a yellow precipitate (D) on treatment with sodium iodide. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Identify the compound (A) to (D).
A=Pb(NO3)2 B=PbCl2 C=PbS D=Pbl2
A=PbSO3 B=PbCl2 C=PbCl D=PbO2
A=Pbl2 B=PbO C=PbH4 D=Pb(NO3)2
A=PbS B=PbCl2 C=Pb(NO3)2 D=Pbl2
- Ferrous nitrate
- Ferric nitrate
- A mixture of NO and NO2
- Nitrosoferrous sulphate
Lead pipes are not suitable for drinking water because
A layer of lead dioxide is deposited over pipes
Lead reacts with air to form litharge
Lead reacts with water containing air to form Pb(OH)2
Lead forms basic lead carbonate
- Heating a mixture of alumina and coke in a current of dry chlorine
- Passing dry HCl gas over heated aluminium powder
- Heating AlCl3.6H2O
- Passing dry chlorine over heated aluminium
- HOCl and HOCl2
- HCl only
- HCl and HClO2
- HCl and HOCl
Basic Lead carbonate is also known as
White Lead
Red Lead
Sugar of Lead
Black Lead
Basic Lead carbonate is also known as
White Lead
Red Lead
Sugar of Lead
Black Lead
- 6 and +3
- 3 and +3
- 4 and +2
- 6 and +1
An aqueous solution of a salt (A) gives white precipitate (B) with sodium chloride solution. The filtrate gives a black precipitate. (C) When H2S is passed into it. Compound (B) dissolves in hot water and the solution gives a yellow precipitate (D) on treatment with sodium iodide. The compound (A) does not give any gas with dilute HCl but liberates a reddish brown gas on heating. Identify the compound (A) to (D).
A=Pb(NO3)2 B=PbCl2 C=PbS D=Pbl2
A=PbSO3 B=PbCl2 C=PbCl D=PbO2
A=Pbl2 B=PbO C=PbH4 D=Pb(NO3)2
A=PbS B=PbCl2 C=Pb(NO3)2 D=Pbl2
- PbS
- Pb(NO3)2
- PbCl2
- PbI2
- SnS
- SnS2
- Sn2S3
- None of these
- 20
- 40
- 23
- None of the above
- diphenylamine
- monophenylamine
- triphenylamine
- pentaphenylamine
If true enter 1, else enter 0.
- Fe3+→Fe2+;NO→NO+
- Fe2+→Fe+;NO→NO+
- Fe2+→Fe3+;NO→NO+
- Fe2+→Fe3+;NO+→NO
- Ink
- Azo-dyes
- Hydrazine
- Paints
- Cupric thiosulphate
- Silver thiosulphate
- Ferric thiosulphate
- Lead thiosulphate
The value of x is:
- phenol
- none of these
- nitrobenzene
- diazo compound
- True
- False