Dehydrohalogenation for Alkenes
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CH3Cl, CH3CH2Cl, (CH3)2CHCl and (CH3)3CCl
- CH3Cl>(CH3)2CHCl>CH3CH2Cl>(CH3)3CCl
- CH3Cl>CH3CH2Cl>(CH3)2CHCl>(CH3)3CCl
- CH3CH2Cl>CH3Cl>(CH3)2CHCl>(CH3)3CCl
- (CH3)2CHCl>CH3CH2Cl>CH3Cl>(CH3)3CCl
Benzene reacts with in presence of produces
- Ethyl nitrite
- Ethane
- Ethene
- Nitroethane
In dehydrohalogenation reactions the preferred product is that alkene which has the greatest number of alkyl groups attached to the doubly bonded carbon atoms. This rule is known as:
Saytzeff's rule
Markoniknov's rule
Anti markoniknov's rule
None of these
Write short notes on chain-shortening and chain-lengthening reactions for sugars.
Predict all the alkanes that would be formed by dehydrohalogenation of the following halides with sodium ethoxide in ethanol and identify the major alkene :
1-bromo-1-menthylcyclohexane
2 -chloro-2-methylbutane
3-bromo- 2, 2, 3-Trimethylpentane.
Which of the following is the major product when 1-butanol is heated with concentrated ?
1-butene
Cis-2-butene
Trans-2-butene
All of these
The dehydrohalogenation of neopentyl bromide with alcoholic KOH mainly gives
- 2, 2-dimethyl-1-butene
- 2-butene
- 2-methyl-1-butene
2-methyl-2-butene
- C2H6
- CH4
- C2H2
- C2H4
- 1
- 2
- 3
- 4
- 1-Butene
- 1-Butyne
- 2-Butene
- All of these
- 4 > 3 > 2 > 1
- 3 > 2 > 1 > 4
- 1 > 3 > 4 > 2
- 1 > 3 > 2 > 4
- CH3CHO
- CH2=CH2
- CH3CH2OCH3CH3
- CH3CH2OK
- 1-Butanol
- 1-Butene
- 2-Butene
- 2-Butanol
- Alkanes
- Alkenes
- Alkynes
Aromatic hydrocarbons
- Dilute H2SO4
- Ethyl alcohol
- Aqueous KOH
- Alcoholic KOH
which of the following alkene will be the major product?
- I
- II
- both will be formed in equal amount
- None of the above
- Ethylene
- Ethane
- Ethyne
- Vinyl bromide
\( \stackrel{\eta}{\longrightarrow} \)
CH3−CH2−Br and CH3−CH3|C|Br−CH3
- 1-Butene
- 1-Butyne
- 2-Butene
- All of these
- C6H5−CH2−CH2−CH2−BrKOH−−−−−→Ethanol
- C6H5−CH2−Br|CH−C6H5KOH−−−−−→Ethanol
- C2H2
- C2H6
- C2H4
- CH4
- (SiH3)2O+BBr3
- (CH3)2O+BF3
- (SiH3)2O+BF3
- (CH3)2O+BBr3